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3. [0/2 Points] DETAILS PREVIOUS ANSWERS Maximize $p = 5x - 4y + 3z$ subject to $10x + 10z \le 100$ $5y - 5z \le 50$ $10x - 5y \le 50$ $x \ge 0, y \ge 0, z \ge 0.$ p = (x, y, z) = ) Need Help? Read It Submit Answer 4. [0/2 Points] DETAILS PREVIOUS ANSWERS WANEF Maximize $p = 14x + 10y + 12z$ subject to $x + y - z \le 3$ $x + 2y + z \le 8$ $x + y \le 5$ $x \ge 0, y \ge 0, z \ge 0.$ p = 10 (x, y, z) = ) Need Help? Read it Watch It

          3. [0/2 Points]
DETAILS
PREVIOUS ANSWERS
Maximize $p = 5x - 4y + 3z$ subject to
$10x + 10z \le 100$
$5y - 5z \le 50$
$10x - 5y \le 50$
$x \ge 0, y \ge 0, z \ge 0.$
p = 
(x, y, z) = 
)
Need Help?
Read It
Submit Answer
4. [0/2 Points]
DETAILS
PREVIOUS ANSWERS
WANEF
Maximize $p = 14x + 10y + 12z$ subject to
$x + y - z \le 3$
$x + 2y + z \le 8$
$x + y \le 5$
$x \ge 0, y \ge 0, z \ge 0.$
p = 
10
(x, y, z) = 
)
Need Help?
Read it
Watch It

3. [0/2 Points]
DETAILS
PREVIOUS ANSWERS
Maximize p = 5x - 4y + 3z subject to
10x + 10z ≤ 100
5y - 5z ≤ 50
10x - 5y ≤ 50
x ≥ 0, y ≥ 0, z ≥ 0.
p =
(x, y, z) =
)
Need Help?
Read It
Submit Answer
4. [0/2 Points]
DETAILS
PREVIOUS ANSWERS
WANEF
Maximize p = 14x + 10y + 12z subject to
x + y - z ≤ 3
x + 2y + z ≤ 8
x + y ≤ 5
x ≥ 0, y ≥ 0, z ≥ 0.
p =
10
(x, y, z) =
)
Need Help?
Read it
Watch It

Added by Virginia H.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Nicole Smina

Step 1

We can solve for y using the quadratic formula: y = (2 ± sqrt(4 + 8)) / 2 y = 1 ± sqrt(3) Since we want y > 0, we take the positive root: y = 1 + sqrt(3) Now we can substitute this value of y into the objective function and maximize: T = 4x + 10y + 122 T = 4x Show more…

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Apps YouTube Maps Gmail Viewing Saved Work Revert [0/2 Points] DETAILS PREVIOUS ANSWERS Maximize p = Sx + 4y + 32 subject to 10x + 10z < 100, Sy + 52 < 50, 10x + Sy < 50, x^2 > 0, Y > 0, 2 > 0. p = Enter an exact number; (x, Y, 2) Need Help? Radilt Submit Answer [0/2 Points] DETAILS PREVIOUS ANSWERS WANEF Maximize T4x + 10y + 122 subject to 2y + 2 = (âˆš.Y^2) Need Help?