Assume that a procedure yields a binomial distribution with n=1321 trials and the probability of success for one trial is p=0.62 . Find the mean for this binomial distribution. (Round answer to one decimal place.) Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value \mu –2\sigma and the maximum usual value \mu +2\sigma . Enter answer as an interval using square-brackets only with whole numbers. usual values =
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Step 1
The mean (μ) of a binomial distribution is given by the formula: μ = n * p where n is the number of trials and p is the probability of success. Plugging in the values: μ = 1321 * 0.62 μ ≈ 818.82 (rounded to one decimal place) Show more…
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