00:01
All right, so to find the value of the right endpoint rim of sum, we need to find the change in x, which just would be b minus a over n.
00:13
So our b, in this case, is 6 minus 2, and the number of rectangles we have is 1, 2, 3, 4, 5, 6, 7, 8.
00:25
So this is just 4 over 8 or just 0 .5.
00:32
So now to calculate the right remissome, we'll have f of xi times change in x.
00:46
This is up to n.
00:52
All right, starting at 1.
00:54
So in this case, if we pull out the change in x, we'll have just 0 .5.
01:01
And this will be times f of 6 plus, i guess we're doing eight of them.
01:11
So f of 5 .5, f of 5, f of 4 .5, f of 4, f of 3 .5, f of 3, and then f of 2 .5...