00:01
All right, so we have a business weekly that conducted a survey of recent grads from top mbas, mba programs.
00:08
And of the survey, we're going to assume that 60 % of recent grads had an annual salary greater than 40 ,000.
00:18
And so those we take a random sample of 51 graduates.
00:24
And the one thing to note here is we're talking about z scores.
00:29
So that's an important thing to note in all of the numbers to 4.
00:33
This one places.
00:34
So we're doing z scores here.
00:36
So find the probability that less than 70 % of the 51 recent graduates have an annual salary exceeding 40 ,000.
00:45
So this starts off as like a binomial distribution, but then we start playing around with the probability shifting around, which tells us we're probably going to be doing something with the normal distribution.
00:57
And that's one of the cool things about the binomial distribution, that you can approximate it with the normal distribution.
01:06
And so there's a few parameters.
01:09
So we look down here, we can see some of the things we need to account for.
01:15
And the thing we need to account for is right here.
01:17
These are questions for us.
01:18
And what assumptions are needed to satisfy the requirements for this problem? it says the last one here.
01:25
X is binomial, and both np and q are at least five.
01:32
That's n is the number in the sample.
01:35
So in this case, n is 51.
01:38
P is the probability, 60 % 0 .6.
01:44
And then q is 1 minus p.
01:48
Q is minus p.
01:52
So in this case, it's 1 minus 0 .6, so it's 0 .4.
01:56
And sure enough, we do.
01:58
They're both bigger than 5, both bigger than 10 even.
02:01
So that's good.
02:03
And then that allows us to approximate the binomial with the normal distribution, which is great because the normal distribution is just so lovely to work with.
02:13
I'll keep the answer there.
02:20
The way we do this is we need to find the mean in standard deviation because that's what we do with the z score.
02:26
We need to find a have an x value minus some mean over the standard deviation.
02:32
So the mean is given as n times p, so that's 30 .6.
02:37
The standard deviation is the square root of n times p times 1 minus p.
02:43
That's this number 3 .49.
02:48
We'll do 3 .5 to make it nice and easy.
02:53
But just, you know, when i did my work, i used the full precision of, i guess i would change this now and i'm looking at it.
03:06
But i was going to say i used the full precision that my spreadsheet gave me.
03:11
But we'll adjust that later on.
03:12
Okay, so we get x is this.
03:23
Oh yeah, so that's right...