Calculate the integral, assuming that $f$ is integrable and $\int_{1}^{b} f(x) dx = 1 - b^{-1}$ for all $b > 0$. $\int_{1}^{6} (8f(x) - 4) dx = \boxed{}$ Enter your answer an simplified form (as an integer or fraction).
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We can use the properties of definite integrals to split the given integral: $\int_{1}^{6} (8f(x) - 4) dx = \int_{1}^{6} 8f(x) dx - \int_{1}^{6} 4 dx$ Show more…
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