Consider the following initial value problem: $y'' + 4y' + 20y = \delta(t - \pi)$; $y(0) = 1$, $y'(0) = 0$ a) Find the solution $y(t)$. NOTE: Denote the Heaviside function by $u_c(t)$ where $u_c(t) = 1$ if $t \ge c$ and 0 otherwise. Indicate separately the exact value of c. $y(t) = $ where $c = $
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We will use the Laplace transform to solve this differential equation. Let $L\{y(t)\} = Y(s)$. The Laplace transform of the derivatives are: $L\{y'(t)\} = sY(s) - y(0)$ $L\{y''(t)\} = s^2Y(s) - sy(0) - y'(0)$ Substitute the initial conditions $y(0) = 1$ and Show more…
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$$\begin{array}{l}{y^{\prime \prime}+y=\delta(t-\pi / 2)} \\ {y(0)=0, \quad y^{\prime}(0)=1}\end{array}$$
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