Consider the function f(x) = x^2 - 4. Part 1: Compute the slope of the tangent line to y = x^2 - 4 at the point (1, -3) using m = \lim_{h \to 0} \frac{f(1 + h) - f(1)}{h} = \boxed{ }
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$f(1 + h) = (1 + h)^2 - 4 = 1 + 2h + h^2 - 4 = h^2 + 2h - 3$ Show more…
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