Consider the line −8x-5y=2 . Find the equation of the line that is parallel to this line and passes through the point −6, 6 . Find the equation of the line that is perpendicular to this line and passes through the point −6, 6 .
Added by Tricia C.
Step 1
Given line: \(-8x - 5y = 2\) Solve for \( y \): \[ -5y = 8x + 2 \] \[ y = -\frac{8}{5}x - \frac{2}{5} \] So, the slope \( m = -\frac{8}{5} \). --- Show more…
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