00:01
Here given the force f is equal to 11 kn and the moment about point a get the vertical force at g summation of ma is equal to 0 that is gy multiplied by ag minus 4 multiplied by ab minus 5 multiplied by ac minus 11 multiplied by ae minus 6 6 multiplied by af is equal to 0.
00:47
From the figure, ag is equal to 12 m, ab is equal to 2 m, ac is equal to 4 m, ae is equal to 8 m and af is equal to 10 m.
01:08
Therefore, gy multiplied by 12 minus 4 multiplied by 2 minus 5 multiplied by 4 minus 11 multiplied by 8 minus 6 multiplied by 10 is equal to 0.
01:32
Therefore, 12 gy -8 -20 -88 -60 is equal to 0 or 12 gy is equal to 176 or gy is equal to 176 divided by 12 that is equal to 14 .66 kn.
02:00
Newton.
02:01
By using the method of joint, consider the free body diagram of the truss.
02:08
Here the angle is theta.
02:12
This is joint h and this is joint i and this is f.
02:21
The force between h and i is fhi and the course between f and i is ffi and here the course is fef and the angle is 5.
02:43
Here f is equal to 6 kn and this point is g and here the force is gy is equal to 14 .66 kn.
03:00
Therefore from the figure theta is equal to tan inverse fh divided by fg...