Current Attempt in Progress Find an equation of the plane that passes through the point P(3, 6, 2) and has the vector n = (1, 4, 8) as a normal. $x + 4y + 8z + 43 = 0$ $x + 4y + 8z = 0$ $x + 4y + 8z - 43 = 0$ $3x + 6y + 2z - 43 = 0$ $3x + 6y + 2z + 43 = 0$
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Step 1: Recall the equation of a plane in 3D space is given by Ax + By + Cz + D = 0, where A, B, and C are the coefficients of the variables x, y, and z, respectively, and D is a constant. Show more…
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Consider point P and vector n. P(0, 0, 0), n = <-8, 6, -1> (a) Find the scalar equation of the plane that passes through P and has normal vector n. 8x - 6y + z = 0 (b) Find the general form of the equation of the plane that passes through P and has normal vector n.
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