Evaluate the integral ∫ sin^2(9) cos(9) dx.
Added by Stephen R.
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Step 1
In our case, $\theta = 9x$, so we have: $$\int \sin(9x)\cos(9x)dx = \frac{1}{2}\int \sin(18x)dx$$ Now, we can integrate $\sin(18x)$ with respect to $x$: Show more…
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