0:00
Hi.
00:01
In this question, we have a subspace v of r4, which is defined by, i'll just write by the plain w -y, w plus y plus, or sorry, w plus x plus y plus c equals 0.
00:16
So i won't write the whole set, but it's defined by this equation, and it is in fact a linear subspace.
00:25
And then we have vectors, which i'll call a this first vector, and then b, i'll call this first vector, and then b, i'll call the second one.
00:44
So first we want to show that a and b can be part of a basis for v.
00:51
So the first thing that we have to show is that these vectors are in v, right? so we have to show that a hat are in v.
01:07
But this is clear.
01:08
I'll just put a green checkmark because, right, it's clear if you plug this in, you have negative 1 plus 1 to 0.
01:13
So it's clear that a and b are in v.
01:18
The second thing we need to show is just that in order for them to be part of a basis, we need them to be linearly independent.
01:36
Nearily independent.
01:40
And so that can be sometimes a difficult process, or we just have to show that one of them is not a multiple of the other.
01:48
And here, well, we can see that the dot product between them is zero, which implies that they're perpendicular.
01:59
Which implies linear independence.
02:04
So that's an easy way of showing that.
02:07
And then finally we want to expand to a, we want to expand this to a basis for v.
02:16
So we need another vector that's in v, and that's linearly independent from the first two.
02:26
Hi, in this, and so the way i did this actually was just by trying different things, because a and b are sort of nice vectors.
02:37
So we need a vector c such that c is in v, and c is linearly independent of a and b...