0:00
Calculus Early Transcendentals
Suppose that a function $f$ is differentiable at $x_{0}$ and define $g(x)=f(m x+b),$ where $m$ and $b$ are constants. Prove that if $x_{1}$ is a point at which $m x_{1}+b=x_{0},$ then $g(x)$ is differentiable at $x_{1}$ and $g^{\prime}\left(x_{1}\right)=m f^{\prime}\left(x_{0}\right)$