Find an equation for the plane through the point (2,1,-4) and parallel to the plane defined by 4x - Ty + 8z = 12. 1 = 4 - 2 - 76 + 4 + 106z - 1 1 = 4 - 2 - T - 1 + 8z + 4 0 = -7(x + 2) + 4 - 1 + 8(z + 4) 0 = 4(-2) - 76 - 1 + 8z + 4
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So, the normal vector is (4, -T, 8). Since we want the plane to be parallel to this plane, the normal vector of our desired plane should also be (4, -T, 8). Show more…
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