Find c and k such that the linear system \begin{cases} x+2y+3z = k\\ x+3y+4z = -2\\ x+4y+cz = -3 \end{cases} has infinitely many solutions.
Added by Michelle A.
Close
Step 1
This means that one equation can be obtained by a linear combination of the other equations. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 71 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine all values of $k$ for which the given linear system has (a) no solution, (b) a unique solution, and (c) infinitely many solutions. $$\begin{aligned} k x_{1}+2 x_{2}-x_{3} &=2, \\ k x_{2}+x_{3} &=2. \end{aligned}$$
Adi S.
For what value(s) of $k$ will the following system of linear equations have no solution? infinitely many solutions? $$\begin{array}{r}x-2 y=3 \\-2 x+4 y=k\end{array}$$
Systems and Matrices
Systems of Equations
For the linear system x1 + 3x2 = 2 3x1 + hx2 = k Find values for h and k such that the system has: a) no solution b) a unique solution c) infinitely many solutions
Piyush Kumar G.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD