To find \(f'(x)\), we use the chain rule. The derivative of \(\sqrt{u}\) with respect to \(u\) is \(\frac{1}{2\sqrt{u}}\), and the derivative of \(8x + 1\) with respect to \(x\) is \(8\). Therefore, applying the chain rule, we get:
\[f'(x) = \frac{1}{2\sqrt{8x +
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