Question

For the given functions f and g, complete parts (a)-(h). $f(x) = x - 6$ $g(x) = 2x^2$ (a) Find $(f + g)(x)$. $(f + g)(x) = \Box$ (Simplify your answer.) (b) Find $(f + g)(3)$. $(f + g)(3) = \Box$ (Type an integer or a simplified fraction.) (c) Find $(f - g)(x)$. $(f - g)(x) = \Box$ (Simplify your answer.) (d) Find $(f - g)(2)$. $(f - g)(2) = \Box$ (Type an integer or a simplified fraction.) (e) Find $(f \cdot g)(x)$. $(f \cdot g)(x) = \Box$ (Simplify your answer.) (f) Find $(f \cdot g)(4)$. $(f \cdot g)(4) = \Box$ (Type an integer or a simplified fraction.) (g) Find $(\frac{f}{g})(x)$. $(\frac{f}{g})(x) = \Box$ (Simplify your answer.) ... . (f)...

Name: for the given functions f and g complete parts a h fx x 6 gx 2x2 a find f gx f gx box simplify your answer b find f g3 f g3 box type an integer or a simplified fraction c find f gx f gx box 17255
Uploaded: 2022-06-30T19:56:20-08:00
Duration: 2 min 50 s
Channel: Teresa Fuston
Description: for the given functions f and g complete parts a h fx x 6 gx 2x2 a find f gx f gx box simplify your answer b find f g3 f g3 box type an integer or a simplified fraction c find f gx f gx box 17255

          For the given functions f and g, complete parts (a)-(h).
$f(x) = x - 6$
$g(x) = 2x^2$

(a) Find $(f + g)(x)$.
$(f + g)(x) = \Box$ (Simplify your answer.)

(b) Find $(f + g)(3)$.
$(f + g)(3) = \Box$ (Type an integer or a simplified fraction.)

(c) Find $(f - g)(x)$.
$(f - g)(x) = \Box$ (Simplify your answer.)

(d) Find $(f - g)(2)$.
$(f - g)(2) = \Box$ (Type an integer or a simplified fraction.)

(e) Find $(f \cdot g)(x)$.
$(f \cdot g)(x) = \Box$ (Simplify your answer.)

(f) Find $(f \cdot g)(4)$.
$(f \cdot g)(4) = \Box$ (Type an integer or a simplified fraction.)

(g) Find $(\frac{f}{g})(x)$.
$(\frac{f}{g})(x) = \Box$ (Simplify your answer.)
... . (f)...

$for the given functions f and g complete parts a h fx x 6 gx 2x2 a find f gx f gx box simplify your answer b find f g3 f g3 box type an integer or a simplified fraction c find f gx f gx box 17255$

Added by Austin S.

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