00:01
All right, so we have some reactions here, and they're delta h values, and these are all in kilojoules, just to be consistent with units.
00:14
Okay, so we want to know what is the, we want to get to this reaction.
00:21
N2o plus n02 makes 3no.
00:32
All right, so we want 3no on the product side.
00:36
The only reaction that we have an o in is already on the product side is reaction b.
00:41
So we need to take three halves of reaction b as written.
00:51
That'll give us, if we multiply by three halves, three halves n2 plus three halves o2 makes three n0 with a delta h of three halves.
01:09
So 1 .5 times 180 .5.
01:13
All right.
01:14
Then, so we've taken care of the product side.
01:17
Now we need to get rid of these things and also get n2 and n2 on the left hand side.
01:23
So let's see.
01:26
N2o shows up here and there's two of them, but we need one.
01:29
So if we take half of a and flip it, then we'll get n2 -n2 makes n2 plus half o2.
01:43
And then our delta h is negative 0 .5 times 164 .1.
02:00
All right...