Given the IP address 173.29.7.135 and a subnet mask of 255.255.255.224, provide the network definition.
Added by Mary A.
Step 1
- IP address: 173.29.7.135 - 173 = 10101101 - 29 = 00011101 - 7 = 00000111 - 135 = 10000111 - Binary representation: 10101101.00011101.00000111.10000111 - Subnet mask: 255.255.255.224 - 255 = 11111111 - 255 = 11111111 - 255 = 11111111 - 224 = Show more…
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Objective: Explain and employ network addressing. For all of the columns below use the IP address: 175.30.101.205 Instructions: The first 3 columns are different ways of viewing the subnet mask. You are given the subnet mask as one of the 3, and you need to complete the other two representations for each row. Complete these 3 columns first. Proceed to complete the Increment by determining the value of the last network bit for the given subnet mask. It is easiest to observe in the binary representation. Since network IDs will always be multiples of the increment (after the zero subnet) – in the octet that holds the last network bit, use the increment to determine the network ID, broadcast, and host range for the IP address displayed above, given the subnet mask for that row. Slash Notation | Binary Subnet Mask | Dotted Decimal Subnet Mask | Increment | Network | Broadcast | Host Range ---|---|---|---|---|---|--- 1 /28 | | | | | | 2 | 11111111.11111111.11111111.11100000 | | | | | 3 | | 255.255.255.192 | | | | 4 /30 | | | | | | 5 | 11111111.11111111.11000000.00000000 | | | | | 6 | | 255.255.240.0 | | | | 7 /22 | | | | | | 8 | 11111111.11111111.11111110.00000000 | | | | | 9 | | 255.255.224.0 | | | | 10 /21 | | | | | |
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