00:01
For question number one, the frequency of the a allele is 0 .5.
00:09
So by this one, we have 0 .30 aa, which is 0 .30 times 2.
00:18
That is 0 .60 .a.
00:22
Alleles.
00:24
We have also 0 .40, that is heterozygos a.
00:29
So 0 .4 a alleles and also 0 .4 for the recessive alleles so 0 .30 recessive a that is 0 .06 which is recessive alleles.
00:52
So for the total alleles we have 0 .6 plus 0 .4 plus 0 .4 plus 0 .4 plus 0 .4 plus 0 .6 is 2.
01:06
So we have the total a alleles that is 0 .6 plus 0 .4 which is 1 .0 and for the recessive alleles that is 0 .4 plus 0 .6 that is 1 .0.
01:25
So the frequency the frequency of your a allele is 1 .0 divided by 2 .0 which is 0 .5.
01:40
For question number two, the mn genotype frequency is 0 .4995.
01:51
So we have the m, 0 .2515, which is 0 .2525 times 2, is 0 .503m allele...