In an even even nucleus with the following sequence of...

Name: in an even even nucleus with the following sequence of levels above 0 ground state 1 89 kev 2 288 kev 1 585 kev 3 1050 kev 2 1129 kev a draw a level scheme and show all of the reasonably pro 34452
Uploaded: 2021-08-05T00:34:33-08:00
Duration: 6 min 51 s
Channel: Ryan Williams
Description: in an even even nucleus with the following sequence of levels above 0 ground state 1 89 kev 2 288 kev 1 585 kev 3 1050 kev 2 1129 kev a draw a level scheme and show all of the reasonably pro 34452

In an even-even nucleus with the following sequence of levels above 0+ ground state: 1- (89 keV), 2- (288 keV), 1+ (585 keV), 3+ (1050 keV), 2+ (1129 keV). a. Draw a level scheme and show all of the reasonably probably gamma transitions and their dominant multipole assignments. b. Based on the size of L and whether the transition is electric or magnetic, which transitions are most likely? Calculate their corresponding gamma ray energies. Which one would be most likely to be seen based on these energies?

Transcript

00:01 In this problem, we want to explain what gamma -ray photons we can see, what we could expect to detect.

00:09 If we know the rotational energy states of a nucleus, which we have five of them, and we know the nucleus can transition between any one of these states.

00:22 And we want to know the possible gamma -ray photons that we can see from the transitions.

00:28 And so we're told to assume that, well, if you use, draw this as rungs on a ladder that are more and more spaced apart as you go up and each rung depicts one energy state then we're told to assume that you can only go down one or two rungs on the ladder nothing else those are the only acceptable transitions and if we go with those assumptions then we just have to we have to figure out all the combinations that you can go down the ladder, essentially.

01:05 And the first, an easiest one is if you start at the very first rung.

01:09 So if you start here and you go down to the last rung.

01:14 So you start at the first energy state, you go down to the zero, with the ground state.

01:18 That's one possibility.

01:20 If you do this, the gamma ray photon emitted will be the difference between the energies of these two states, which are given as 100 .1 minus 0 k -ev, which is just 100 .1.

01:35 K -ev.

01:36 That's one possible photon we can see.

01:39 And that's the only transition that we can make from that first state.

01:42 So that one is done.

01:44 If we start on the second rung of the latter, we can go down one rung and then go down from the first to the zero -th, per se.

01:55 But this second transition we've already considered.

01:57 That's just the first gamma ray photon we would see.

01:59 We would just see the 100 .1 again.

02:02 But if we go from the third rung down, to the second, the change in energies will be e2 minus e sub 1, and that'll be 300 .9 minus 100 .1 kev, which is 200 .8 kev.

02:23 So that's another photon.

02:24 So if we go through this sequence, we'll see a 200 .8 be emitted and then 100 .1 be emitted.

02:31 But we've already considered that we can see 100 .1, so we don't need to consider it again.

02:37 The other possibilities, of being on the second rung is that we can go down two rungs.

02:43 So we can skip over this first one and go straight to the ground state.

02:46 That's another possibility.

02:48 And it'll lead to a third and different photon.

02:51 So if we go from the third state down to the ground state, or should i say the second state down to the ground, we'll go from 300 .9 down to zero, which will just be 300 .9 kev...

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