00:01
For the first part of the problem, for a practice problem, we will use the same procedure that is used in the example given in order to find the uncertainty in a position.
00:14
So we know that momentum is simply mass times the velocity.
00:20
Mass for electron is 9 .11 times 10 to the power minus 31 kg.
00:25
This times the given speed or velocity of electron, that is a 4 .76 times 10 to the power 3 meter per second.
00:35
And this gives us a momentum, p of 43 .36 times 10 to the power minus 28 kg meter per second.
00:51
Now the uncertainty percentage we have is a 0 .0 .0 .000.
01:01
0200280.
01:03
So we had a percentage given that is 0 .00280 in percentage.
01:10
We divided this by 1 ,100, sorry, to get the percentage in simple number.
01:18
And then we multiplied with this momentum to get the uncertainty in a momentum.
01:23
So 43 .36 times 10 to the power minus 28.
01:28
We'll multiply it.
01:29
Apply with the uncertainty here that is 0 .000000 to get the uncertainty and this uncertainty we get here is 1 .21 times 10 to the power minus 31 kg meter per second.
01:46
So now we have uncertainty in momentum we can easily find the uncertainty in the position by using a heisenberg uncertainty principle that says the uncertainty, the product of uncertainty in position.
01:59
Times the product of uncertainty.
02:03
Momentum is equal or greater than h divided by 4 pi, where h is the point constant...