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Q1) A circular cross-sectional pipe with length L=2.5n meter and diameter D=2n meter is filled halfway with water. a) Calculate the resultant hydrostatic pressure force exerted by water on the pipe section A-B only. b) Calculate the point of action of the force components. $\rho_{water}$ = 1000n $kgm^{-3}$ n=(k+1) where k is the last digit of your student number. [For instance; if diameter is given as D=100n cm or D=100xn cm and the student number is 15043039, then k=9 and n=(9+1)=10 and $D_{pipe}$=100\times10=1000 cm]

          Q1) A circular cross-sectional pipe with length
L=2.5n meter and diameter D=2n meter is filled
halfway with water.
a) Calculate the resultant hydrostatic pressure force
exerted by water on the pipe section A-B only.
b) Calculate the point of action of the force
components.
$\rho_{water}$ = 1000n $kgm^{-3}$
n=(k+1) where k is the last digit of your student number.
[For instance; if diameter is given as D=100n cm or D=100xn cm and the student number is 15043039, then
k=9 and n=(9+1)=10 and $D_{pipe}$=100\times10=1000 cm]
        
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Q1) A circular cross-sectional pipe with length
L=2.5n meter and diameter D=2n meter is filled
halfway with water.
a) Calculate the resultant hydrostatic pressure force
exerted by water on the pipe section A-B only.
b) Calculate the point of action of the force
components.
ρwater = 1000n kgm^-3
n=(k+1) where k is the last digit of your student number.
[For instance; if diameter is given as D=100n cm or D=100xn cm and the student number is 15043039, then
k=9 and n=(9+1)=10 and Dpipe=100×10=1000 cm]

Added by Marissa J.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Q1 A circular cross-sectional pipe with length L = 2.5n meters and diameter D = 2n meters is filled halfway with water. a) Calculate the resultant hydrostatic pressure force exerted by water on the pipe section A-B only. D b) Calculate the point of action of the force components. Pwater = 1000n kg/m^3 n = (k + 1) where k is the last digit of your student number [For instance; if diameter is given as D = 100n cm or D = 100xn cm and the student number is 150A3039, then k = 9 and n = 9 + 1 = 10 and Dpipe = 10010 = 1000 cm]
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Transcript

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00:01 Hello students here in the question we apply the bernoulli's equation between the cross -sectional area of the pipe that is p1 plus 0 .5 into rho v1 square plus rho g into z1 equals to p2 plus 0 .5 into rho v2 square plus rho g z2.
00:34 Now since the water is flowing horizontally so the vertical velocity v1 and v2 are negligible so the equation becomes as p1 plus rho g z1 equals to p2 plus rho g z2.
00:54 Now we are given that z2 is equal to z1 plus h which is where h is the vertical height so we can again rewrite the equation as p2 equals to p1 plus rho g h...
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