Let A = B = C = { x | x is a real number}. Let f(a) = 3a+15 and g(b) = 2b^2 be defined as follows: (a) f(4) = 3(4) + 15 = 12 + 15 = 27 (b) g(1) = 2(1)^2 = 2(1) = 2 (c) g(x-1) = (x-1)^2 (d) f(x^2) = x^2 - 1 (e) f(x-1) = (x-1)^2 - 1 = x^2 - 2x + 1 - 1 = x^2 - 2x (f) g(y^2) = 2(y^2)^2 = 2y^4
Added by Luz B.
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So, we get: f(4) = 3(4) + 15 = 12 + 15 = 27 Show more…
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