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Problem 1: Solve each inequality symbolically and state the solution set using interval notation. a. $\frac{3y}{4} + \frac{2y+1}{8} \le 5y$ b. $\frac{4x}{3} + \frac{1-8x}{2} \ge 7x$ c. $-1 \le \frac{3-2t}{7} < 2$ d. $-3 < \frac{2-5x}{3} \le 1$

Name: problem 1 solve each inequality symbolically and state the solution set using interval notation a frac3y4 frac2y18 le 5y b frac4x3 frac1 8x2 ge 7x c 1 le frac3 2t7 2 d 3 frac2 5x3 le 1 98343
Uploaded: 2021-12-29T18:18:14-08:00
Duration: 3 min 26 s
Channel: Mirza Aslam Beig
Description: problem 1 solve each inequality symbolically and state the solution set using interval notation a frac3y4 frac2y18 le 5y b frac4x3 frac1 8x2 ge 7x c 1 le frac3 2t7 2 d 3 frac2 5x3 le 1 98343

          Problem 1: Solve each inequality symbolically and state the solution set using interval notation.
a. $\frac{3y}{4} + \frac{2y+1}{8} \le 5y$
b. $\frac{4x}{3} + \frac{1-8x}{2} \ge 7x$
c. $-1 \le \frac{3-2t}{7} < 2$
d. $-3 < \frac{2-5x}{3} \le 1$

$problem 1 solve each inequality symbolically and state the solution set using interval notation a frac3y4 frac2y18 le 5y b frac4x3 frac1 8x2 ge 7x c 1 le frac3 2t7 2 d 3 frac2 5x3 le 1 98343$

Added by Wendy O.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Mirza Aslam Beig

12/29/2021

Step 1

$8 \left( \frac{3y}{4} \right) + 8 \left( \frac{2y+1}{8} \right) \le 8 (5y)$ $2(3y) + (2y+1) \le 40y$ $6y + 2y + 1 \le 40y$ $8y + 1 \le 40y$ Subtract $8y$ from both sides: $1 \le 40y - 8y$ $1 \le 32y$ Divide by 32: $\frac{1}{32} \le y$ So, $y \ge \frac{1}{32}$. In Show more…

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Problem 1: Solve each inequality symbolically and state the solution set using interval notation. a. $\frac{3y}{4} + \frac{2y+1}{8} \le 5y$ b. $\frac{4x}{3} + \frac{1-8x}{2} \ge 7x$ c. $-1 \le \frac{3-2t}{7} < 2$ d. $-3 < \frac{2-5x}{3} \le 1$