Question 1 Which of the following is the best substitution for the indefinite integral $$ \int \frac{x^3}{\sqrt{x^2-1}} dx $$ $$ x = \sin \theta $$ $$ x = \sec \theta $$ $$ u = x^2 - 1 $$ $$ x = \tan \theta $$ Question 2 5 pts 5 pts
Added by Donald M.
Close
Step 1
The integral is of the form $$ \int \frac{x^3}{\sqrt{x^2-1}} dx $$. We need to find the best substitution to simplify this integral. Show more…
Show all steps
Your feedback will help us improve your experience
Khushbu Rani and 81 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Khushbu R.
Jason H.
Multiple Choice To find $\int \sqrt{x^{2}-9} d x,$ use the substitution $x=[($ a) $\sec \theta,$ (b) $3 \sin \theta,$ (c) $3 \sec \theta,$ (d) $3 \tan \theta]$.
Techniques of Integration
Integration Using Trigonometric Substitution: Integrands Containing $\sqrt{a^{2}-x^{2}}, \sqrt{x^{2}+a^{2}}$, or $\sqrt{x^{2}-a^{2}}$ $a>0$
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD