Question

QUESTION 2: Find the focus and directrix of the parabola with the given equation. 3x^2 = -5y Options: 1. Focus: (-(5)/(12),0), directrix: x=(5)/(12) 2. Focus: (0,(5)/(12)), directrix: y=-(5)/(12) 3. Focus: (0,-(5)/(12)), directrix: y=(5)/(12) 4. Focus: [0,-(5)/(3)), directrix: y=(5)/(3)

Name: question 2 find the focus and directrix of the parabola with the given equation 3x2 5y options 1 focus 5120 directrix x512 2 focus 0512 directrix y 512 3 focus 0 512 directrix y512 4 focus 0 55046
Uploaded: 2020-11-04T00:25:53-08:00
Duration: 3 min 47 s
Channel: Kirsten Bauck
Description: question 2 find the focus and directrix of the parabola with the given equation 3x2 5y options 1 focus 5120 directrix x512 2 focus 0512 directrix y 512 3 focus 0 512 directrix y512 4 focus 0 55046

          QUESTION 2: Find the focus and directrix of the parabola with the given equation.

3x^2 = -5y

Options:

1. Focus: (-(5)/(12),0), directrix: x=(5)/(12)
2. Focus: (0,(5)/(12)), directrix: y=-(5)/(12)
3. Focus: (0,-(5)/(12)), directrix: y=(5)/(12)
4. Focus: [0,-(5)/(3)), directrix: y=(5)/(3)

Added by Esperanza H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kirsten Bauck

11/04/2020

Step 1

The given equation is 3x^2 = -5y. To rewrite it in the standard form, we need to isolate y on one side of the equation. Dividing both sides by -5, we get: y = -(3/5)x^2 Show more…

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QUESTION 2: Find the focus and directrix of the parabola with the given equation. 3x^2 = -5y Options: 1. Focus: (-(5)/(12),0), directrix: x=(5)/(12) 2. Focus: (0,(5)/(12)), directrix: y=-(5)/(12) 3. Focus: (0,-(5)/(12)), directrix: y=(5)/(12) 4. Focus: [0,-(5)/(3)), directrix: y=(5)/(3)