Question 33 What is the purpose of the following code? current = head; while (current != NULL) { //Process current current = current->link; } Traversal of a linked list Creation of a new list Insertion of a node Selection of a node
Added by Toni S.
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Step 1: The code initializes a pointer `current` to the head of a linked list. Show more…
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i would like to know how to solve this thanks.
Yujie W.
1. initialize three pointers: prev to None, curr to the head of the linked list, and next to None. 2. Iterate through the linked list using a loop. 3. Inside the loop, before changing the next pointer of curr, store the next node in the next variable. next_node = curr.next 4. Update the next pointer of curr to point to the previous node, i.e., curr.next = prev 5. Update the prev pointer to the current node and curr to the next node using the next variable. _______________ _______________
Akash M.
void LL::deleteNode(el_t e) { node* del; if (isEmpty()) { // Must be outside the for Loop cout << "[empty]" << endl; return; } else { del = front; front = front->next; delete del; // Delete the node pointed } } If the element does not exist, return. else if (pre->next == NULL) { // If the element does not exist return; } else { deleteRear(); // Link the node before } bool LL::search(el_t key) { node* p = front; while (p != NULL) { if (p->elem == key) { return true; } p = p->next; } return false; }
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