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Question 5 5 pts The fraction $$ \frac{ax^3+bx^2+cx+d}{(x^2+1)(x^2-4)} $$ will take which form when expressed as partial fractions? $$ \frac{Ax+B}{x^2+1} + \frac{Cx+D}{x^2-4} $$ $$ \frac{A}{x^2+1} + \frac{B}{x+2} + \frac{C}{x-2} $$ $$ \frac{Ax+B}{x^2+1} + \frac{C}{x^2-4} $$ $$ \frac{Ax+B}{x^2+1} + \frac{C}{x+2} + \frac{D}{x-2} $$

Name: question 5 5 pts the fraction fracax3bx2cxdx21x2 4 will take which form when expressed as partial fractions fracaxbx21 fraccxdx2 4 fracax21 fracbx2 fraccx 2 fracaxbx21 fraccx2 4 fracaxbx21 f 11989
Uploaded: 2023-03-31T05:00:24-08:00
Duration: 1 min 45 s
Channel: Khushbu Rani
Description: question 5 5 pts the fraction fracax3bx2cxdx21x2 4 will take which form when expressed as partial fractions fracaxbx21 fraccxdx2 4 fracax21 fracbx2 fraccx 2 fracaxbx21 fraccx2 4 fracaxbx21 f 11989

          Question 5
5 pts
The fraction $$ \frac{ax^3+bx^2+cx+d}{(x^2+1)(x^2-4)} $$ will take which form when expressed as partial fractions?
$$ \frac{Ax+B}{x^2+1} + \frac{Cx+D}{x^2-4} $$
$$ \frac{A}{x^2+1} + \frac{B}{x+2} + \frac{C}{x-2} $$
$$ \frac{Ax+B}{x^2+1} + \frac{C}{x^2-4} $$
$$ \frac{Ax+B}{x^2+1} + \frac{C}{x+2} + \frac{D}{x-2} $$

$question 5 5 pts the fraction fracax3bx2cxdx21x2 4 will take which form when expressed as partial fractions fracaxbx21 fraccxdx2 4 fracax21 fracbx2 fraccx 2 fracaxbx21 fraccx2 4 fracaxbx21 f 11989$

Added by Remedios M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Khushbu Rani

03/31/2023

Step 1

We need to express this fraction in partial fractions. First, factor the denominator completely. The term $$(x^2+1)$$ is an irreducible quadratic factor over real numbers because its discriminant is $0^2 - 4(1)(1) = -4 < 0$. The term $$(x^2-4)$$ is a difference Show more…

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Question 5 5 pts The fraction $$ \frac{ax^3+bx^2+cx+d}{(x^2+1)(x^2-4)} $$ will take which form when expressed as partial fractions? $$ \frac{Ax+B}{x^2+1} + \frac{Cx+D}{x^2-4} $$ $$ \frac{A}{x^2+1} + \frac{B}{x+2} + \frac{C}{x-2} $$ $$ \frac{Ax+B}{x^2+1} + \frac{C}{x^2-4} $$ $$ \frac{Ax+B}{x^2+1} + \frac{C}{x+2} + \frac{D}{x-2} $$