Repair Example 9.2 in case of: min belt length is 2300...

Repair Example 9.2 in case of: min belt length is 2300 mm. Design a V-belt drive to transmit power from a motor rotating at 1440 rev/min and rated at 15 kW to a fan rotating at 720 rev/min. Centers are to be near to, but not more than 750 mm apart, min belt length is 2300 mm, and the driven pulley is not to exceed 355 mm outside diameter.

Transcript

00:01 Hello students, let us note down the given data, power 90 kw, speed of the compressor, electric motor, diameter, center distance of the pulley, speed, area, density, tensile stress, angle of the pulley, coefficient of the friction.

01:03 These are all the given data.

01:06 First we need to calculate diameter of the motor which is given by speed ratio is equal to diameter ratio.

01:18 In this diameter of the motor d1 will be equal to n2 by n1 into d2.

01:25 Now substituting the values here 250, 750 and 1 meter we get d2 as 0 .333 meter.

01:38 Now mass of the belt is obtained by multiplying volume into density.

01:43 Volume is given by area into length into density.

01:47 Substituting the values here 375 into 10 power minus 6, density 1000, from this we get 0 .375 kg.

02:02 Now centrifugal tension is given by mass into speed square where mass is 0 .375, speed 1600 per minute is given, converting it to per second divide it by 60.

02:18 We get 266 .66 newton.

02:24 Maximum tension in the belt is given by product of stress and area.

02:35 Substituting for stress that is 2 .5 mega pascal, area 375 millimeter square, we get maximum stress as 937 .5 newton where maximum stress is the sum of stress of the compressor and centrifugal stress.

03:01 From this compressor stress will be equal to maximum stress minus centrifugal stress.

03:09 Substituting for maximum and centrifugal stress we get 670 .833 newton...

Question

Please give Ace some feedback