Required information three horizontal forces are applied to...

Name: required information three horizontal forces are applied to a vertical cast iron arm as shown in the figure p a 150 mm b 600 n 150 mm c 400 n 150 mm d determine the resultant of the forces a 72969
Uploaded: 2020-12-16T18:53:58-08:00
Duration: 6 min 7 s
Channel: Pawan Yadav
Description: required information three horizontal forces are applied to a vertical cast iron arm as shown in the figure p a 150 mm b 600 n 150 mm c 400 n 150 mm d determine the resultant of the forces a 72969

Required information Three horizontal forces are applied to a vertical cast iron arm as shown in the figure. P A 150 mm B 600 N 150 mm C 400 N 150 mm D Determine the resultant of the forces and the distance from the ground to its line of action when $P = 6,400 N$. The resultant of the forces (R) Is N (Click to select) The distance from the ground to its line of action (y) is m. (Round the final answer to three decimal places.)

Transcript

00:01 So we are given three horizontal forces applied on a cast iron arms as shown in the diagram.

00:04 And we determine the resultant force.

00:05 So we need to find r and the line of action of that force from the ground for p equals to 214 ,000 newtons.

00:12 Okay, so let's solve for p equals to 200 newton.

00:16 So the resultant force, that is, summation of f is equals to, so we can, since all the forces are horizontal, there will be only horizontal component acting.

00:25 So summation of force fx and that is a resultant force r and that is equals to p is acting rightwards so we'll take it as positive then this force is acting leftwards negative and this is acting leftwards this is also negative so we get 200 minus 600 and that gives us minus 800 newton so this is the resultant force so now to calculate moment at d from the ground point so we can calculate this is given by r times f right so first force will take the counterclockwise direction as positive.

01:01 So here 400 is acting in this direction so it will try to rotate the body counterclockwise and it is a distance of 150 mm so 0 .15 meter times 400.

01:13 This 600 will also try to rotate counterclockwise so and it is a distance of 300 amm which is 0 .3 times 600 and the last one this p is trying to rotate the body clockwise so we'll take it as positive and p is given to us this is 200 times the distance is 450 m which is 0 .45.

01:32 Okay, so on calculating this, we get md is equal to 150 newton meter.

01:37 Okay, so now it shows that body is trying to rotate counterclockwise and the resultant force is minus 800 newton, which means it is acting from right to left.

01:48 Okay, so now we need to find the line of action of this force.

01:51 So assuming this force is acting in this direction at distance of x from d.

01:57 Now the resultant force producing the moment at d must be equal to the moment we obtained from all this independent forces.

02:07 So therefore, r times small r, that is the radius or, sorry, x, we have taken x.

02:13 So x times the force acting that is r, the resultant force, must be equals to md.

02:18 So x is how much? we don't know.

02:20 We need to find it.

02:21 R, we know resultant force is 800 newton.

02:24 And this minus was because of force acting in this...

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