00:01
So let us start with the concept which we are going to use here for this question.
00:09
So basically, we have defined the grand canonical potential as q is equals to u minus ts minus mu n.
00:26
Let's say equation first, where u is what? the internal energy, ts are the temperature and entropy, n is the total number of particles in the system, mu is the chemical potential.
00:46
So now, this difference of q, this can be calculated as dq is equals to du minus t ds minus s dt minus mu dn minus n dmu.
01:14
Means we have just applied here u into v formula in between these two after applying the derivative.
01:23
So this will be goes to du minus of t ds minus of mu dn minus s dt minus n dmu.
01:38
So this can be given as dq is equals to minus of p dv minus of s dt minus of n dmu.
01:51
Let's say equation two.
01:53
And how did we written as? because the first law of thermodynamic says that du is equals to t ds minus p dv plus mu dn...