Question

Suppose to have the following electrical diagram: used with a voltage source input of 3Vpp and 3Vdc. Represent the system RBD and evaluate the system reliability supposing that the failure rates of diodes are $10^{-5}$ [f/h], the transformer is $10^{-5}$ and the RC group is $10^{-7}$. Repeat the exercise if Vdc is 0 and compare the results.

          Suppose to have the following electrical diagram:

used with a voltage source input of 3Vpp and 3Vdc. Represent the system RBD and evaluate
the system reliability supposing that the failure rates of diodes are $10^{-5}$ [f/h], the transformer is
$10^{-5}$ and the RC group is $10^{-7}$. Repeat the exercise if Vdc is 0 and compare the results.
        
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Suppose to have the following electrical diagram:

used with a voltage source input of 3Vpp and 3Vdc. Represent the system RBD and evaluate
the system reliability supposing that the failure rates of diodes are 10^-5 [f/h], the transformer is
10^-5 and the RC group is 10^-7. Repeat the exercise if Vdc is 0 and compare the results.

Added by Carmen W.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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Suppose we have the following electrical diagram: 1211 11 It is used with a voltage source input of 3Vpp and 3Vdc. Represent the system RBD and evaluate the system reliability, assuming that the failure rates of diodes are 10[f/h], the transformer is 10, and the RC group is 107. Repeat the exercise if Vdc is 0 and compare the results.
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Transcript

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00:01 So, the question is to use iterative analysis to determine the diode current where vdd is 1 volt, r is 1 kilo -oom, and is is 10 -10 to minus 15 ampere and the circuit is given here.
00:11 Okay, so we can start by assuming that the voltage across the diode is, let's say, 0 .7 volts because that is the general value that we have for voltage drop across a diode.
00:28 So we'll rate this as vds .7.
00:31 Now we'll use our iterative method.
00:34 So now we know vd, so we can calculate current id.
00:38 So id will be change in voltage divided by resistance.
00:42 So here we have change in voltage that is vdd minus vd over resistance r.
00:50 Now vdd given to us is 1 volt minus 0 .7 divided by 1000 gives 0 .7.
01:00 3mm .mere.
01:04 Okay, so we know the current now for this given value but we don't know if this is correct or not.
01:09 So we have to check what is the vd based on the equation of voltage across the diode.
01:18 So we have vd is equals to vt times ln of id over is.
01:29 Now here vt is the voltage dependent on the temperature.
01:33 And the saturation values, so that is for normal diode or for this given diode is 0 .025 times ln of id we have calculated 0 .3 milliampiers, which is nothing but 0 .3 into 10 to minus 3 ampers divided i .s given to us as 10 to minus 15.
01:57 On calculating this, we get 0 .6607.
02:02 So from this we get vda 0 .6 in here with 0 .7s.
02:07 So now we have one step closer to the actual value.
02:12 So now we can again use the same procedure...
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