Question

Texts: A rubber ball of mass m = 0.450 kg fell from an unknown height and strikes the concrete floor 1.05 s after release, then rebounds to a height of 2.75 m. Calculate: a) The initial height of the ball above the ground at release. b) The speed with which the ball struck the floor. c) The speed with which it rebounded. d) The change in velocity due to the impact.

Name: texts a rubber ball of mass m 0450 kg fell from an unknown height and strikes the concrete floor 105 s after release then rebounds to a height of 275 m calculate a the initial height of the 20371
Uploaded: 2022-06-06T08:23:21-08:00
Duration: 2 min 37 s
Channel: Mayukh Banik
Description: texts a rubber ball of mass m 0450 kg fell from an unknown height and strikes the concrete floor 105 s after release then rebounds to a height of 275 m calculate a the initial height of the 20371

          Texts: A rubber ball of mass m = 0.450 kg fell from an unknown height and strikes the concrete floor 1.05 s after release, then rebounds to a height of 2.75 m. Calculate:

a) The initial height of the ball above the ground at release.
b) The speed with which the ball struck the floor.
c) The speed with which it rebounded.
d) The change in velocity due to the impact.

Added by Kristen J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Mayukh Banik

06/06/2022

Step 1

The equation is given by: h = (1/2)gt^2 where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time. Rearranging the equation, we have: h = (1/2)gt^2 2h = gt^2 2h/g = t^2 t = sqrt(2h/g) Given that t = 1.05 s, we can Show more…

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Texts: A rubber ball of mass m = 0.450 kg fell from an unknown height and strikes the concrete floor 1.05 s after release, then rebounds to a height of 2.75 m. Calculate: a) The initial height of the ball above the ground at release. b) The speed with which the ball struck the floor. c) The speed with which it rebounded. d) The change in velocity due to the impact.