00:01
In this question we have to find that two subdivisions given a which is equal to set 2 .3 .4 and set b which is equal to 6 .8 .10 and a relation b from a to b such that for all x comma y belongs to a cross b and x comma y belongs to r.
00:37
If y such that x is on, indeed.
00:48
Here, a cross b which is equal to 2 .6, 2 .8, 2 .10, 3 .6, 3 .8, 3 .10.
01:03
4 .6, 4 .8 and 4 .10.
01:10
So, hence the relation, 4 which is equal to.
01:15
2 .6, 2 .8, 2 .10, 3 .6 and 4 .8.
01:26
The subduition is 4 not relation to 6...