The curve y=x^(3) has a tangent that passes the point (x,y)=(0,16). Find the tangent point, that is, the point with coordinates (x,y)=(x,x^(3)) on the curve where the slopes of the curve and of the tangent are the same
Added by Sandra C.
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The curve is \( y = x^3 \). The derivative (slope of the tangent) is \( \frac{dy}{dx} = 3x^2 \). Show more…
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