The domain of f(x) = sin^(-1)(n(5)) is [0, x] or (0, 3e].
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The function sin(x) takes an input x (in radians) and returns the sine of that angle. The function 1~'(n(5)) means that we are taking the nth derivative of the function x^5. So, putting it all together, fkx) = sin 1~'(n(5)) means that we are taking the sine Show more…
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