The expression \(\sqrt[6]{x^4y^2} = x^ry^s\) where \(x\) and \(y\) are non-negative real numbers. \(r\), the exponent of \(x\), is: \(s\), the exponent of \(y\), is:
Added by Julia B.
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We have: Vz * y * xys Now, let's combine the terms with the same base. We have x and y as bases, so we get: x^5 * y^s Now, we can see that the exponent of x is 5 and the exponent of y is s. Show more…
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