Question

The function y is defined as y = \begin{cases} \frac{2\exp(x)}{2 + x^2} & \text{if } x \le 0\\ \frac{\exp(-x)}{1 + x^2} & \text{if } x > 0 \end{cases} Using a for loop or otherwise, (a) Determine the values of y in a vector called z for x values from -2 to 2 in steps of 0.2. Display the values of vector z. (b) Determine and display the sum of values of the vector z.

          The function y is defined as
y = \begin{cases} \frac{2\exp(x)}{2 + x^2} & \text{if } x \le 0\\ \frac{\exp(-x)}{1 + x^2} & \text{if } x > 0 \end{cases}
Using a for loop or otherwise,
(a) Determine the values of y in a vector called z for x values from -2 to 2 in steps of 0.2.
Display the values of vector z.
(b) Determine and display the sum of values of the vector z.

The function y is defined as
y = (2(x))/(2 + x^2) if x ≤0
((-x))/(1 + x^2) if x > 0
Using a for loop or otherwise,
(a) Determine the values of y in a vector called z for x values from -2 to 2 in steps of 0.2.
Display the values of vector z.
(b) Determine and display the sum of values of the vector z.

Added by Carolyn S.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Nick Collins

Step 1

2, we can use a for loop. Here's how you can do it in MATLAB: ```matlab x = -2:0.2:2; % create a vector of x values from -2 to 2 in steps of 0.2 z = zeros(size(x)); % initialize a vector z with zeros for i = 1:length(x) if x(i) > 0 z(i) = Show more…

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The function y is defined as: y = 2e^(x-0.5x^2) + 2e^(-x) if x > 0, 1 + x^2 Using a for loop or otherwise: a) Determine the values of y in a vector called z for x values from -2 to 2 in steps of 0.2. Display the values of vector z. b) Determine and display the sum of values of the vector z.