The horizontal asymptote of 2 f(x) = (ex + x) is y = e? 0 y = √e 0 y = 1 y = 2
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We can use L'Hopital's rule to simplify the expression: lim (ex+x)* / 2 x->±∞ = lim (ex+x) / 2* x->±∞ = lim ex + 1 / 2 x->±∞ Since the exponential function grows much faster than the linear function, the limit approaches infinity. Show more…
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