unknown numbxr determination 10 ml 30 hml deterinination 2 id ml 32sn2 ml 0 0 ml 31 4ml 225 ml 0

Name: unknown numbxr determination 10 ml 30 hml deterinination 2 id ml 32sn2 ml 0 0 ml 31 4ml 225 ml 00borm xgs 16 xlo 3 ix 0 1446 i0 9sxl0 4 0 4 volunte 0f unknown usce ml final buret reuling ml 80952
Uploaded: 2023-05-26T23:55:20-08:00
Duration: 2 min 6 s
Channel: Numerade
Description: unknown numbxr determination 10 ml 30 hml deterinination 2 id ml 32sn2 ml 0 0 ml 31 4ml 225 ml 00borm xgs 16 xlo 3 ix 0 1446 i0 9sxl0 4 0 4 volunte 0f unknown usce ml final buret reuling ml 80952

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Question

Unknown Number Determination 10 mL 30 mL Determination 2 mL 32 mL, 2 mL 0 mL 31 mL, 4 mL 22.5 mL, 0.04 M X (gs 16' X10 ~ 3 Ix /0" 1.446 x10" 4,% * {0-4 Volume of unknown Use/mL Final buret reading/mL Initial buret reading/mL Volume of NaOH solution used/mL Molarity of NaOH solution/mol/L Moles of NaOH/mol (Show how you set up this calculation) Moles of H+ displaced by Cu+ (Show simple calculation) Moles of Cu+ on column (Show simple calculation) Concentration of Cu+ sample/mol (Show simple calculation) Average Concentration of Cu+ sample/mol/L (to be calculated) (LL5) 0.007 x10^6 moles Moles NaOH used (225 mL) = 0.0019 moles H+ = (0.0019 moles)/(1.9 x10^-5 moles) = 1.9 x10^-4 Mole Tmole NaOH = 0.095 x10^6 moles (0.0019 moles)/(4 x10^-5) = (x+2) / 2 Able s = 2 moles REPORT SHEET GL 9.9 x10^4 (0.04 M) |adle ~@eJris 1 x 22 moles

          Unknown Number
Determination 10 mL 30 mL
Determination 2 mL 32 mL, 2 mL 0 mL 31 mL, 4 mL 22.5 mL, 0.04 M X (gs 16' X10 ~ 3 Ix /0" 1.446 x10" 4,% * {0-4
Volume of unknown Use/mL
Final buret reading/mL
Initial buret reading/mL
Volume of NaOH solution used/mL
Molarity of NaOH solution/mol/L
Moles of NaOH/mol (Show how you set up this calculation)
Moles of H+ displaced by Cu+ (Show simple calculation)
Moles of Cu+ on column (Show simple calculation)
Concentration of Cu+ sample/mol (Show simple calculation)
Average Concentration of Cu+ sample/mol/L (to be calculated) (LL5) 0.007 x10^6 moles
Moles NaOH used (225 mL) = 0.0019 moles
H+ = (0.0019 moles)/(1.9 x10^-5 moles) = 1.9 x10^-4 Mole
Tmole NaOH = 0.095 x10^6 moles
(0.0019 moles)/(4 x10^-5) = (x+2) / 2
Able s = 2 moles
REPORT SHEET GL 9.9 x10^4 (0.04 M) |adle ~@eJris 1 x 22 moles

unknown numbxr determination 10 ml 30 hml deterinination 2 id ml 32sn2 ml 0 0 ml 31 4ml 225 ml 00borm xgs 16 xlo 3 ix 0 1446 i0 9sxl0 4 0 4 volunte 0f unknown usce ml final buret reuling ml 80952

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