Use the Fundamental Theorem to evaluate the definite integral exactly. $$ \int_{1}^{3} 18x^2 dx = i $$
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The Fundamental Theorem of Calculus states that if $F(x)$ is an antiderivative of $f(x)$, then $$ \int_{a}^{b} f(x) dx = F(b) - F(a) $$ In this case, $f(x) = 18x^2$, $a = 1$, and $b = 3$. Show more…
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