Question

Which of the following is equal to $$ \mathcal{L}^{-1} \left\{ \frac{s^2 + 2s + 1}{(s^2 + 1)^2} \right\} $$ if s > 0 ? (a) (1+t) sin t (b) t+tsinh t (c) t-tcos t (d) (1-t) sint (e) t-t/2 cosht

Name: which of the following is equal to mathcall 1 left fracs2 2s 1s2 12 right if s 0 a 1t sin t b ttsinh t c t tcos t d 1 t sint e t t2 cosht 53695
Uploaded: 2022-02-09T05:35:54-08:00
Duration: 2 min 52 s
Channel: Harsha M
Description: which of the following is equal to mathcall 1 left fracs2 2s 1s2 12 right if s 0 a 1t sin t b ttsinh t c t tcos t d 1 t sint e t t2 cosht 53695

          Which of the following is equal to  $$ \mathcal{L}^{-1} \left\{ \frac{s^2 + 2s + 1}{(s^2 + 1)^2} \right\} $$
if s > 0 ?
(a) (1+t) sin t
(b) t+tsinh t
(c) t-tcos t
(d) (1-t) sint
(e) t-t/2 cosht

$which of the following is equal to mathcall 1 left fracs2 2s 1s2 12 right if s 0 a 1t sin t b ttsinh t c t tcos t d 1 t sint e t t2 cosht 53695$

Added by Pilar V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Harsha M

02/09/2022

Step 1

Step 1: We can rewrite the given function as: $$ \frac{s^2 + 2s + 1}{(s^2 + 1)^2} = \frac{s^2 + 1}{(s^2 + 1)^2} + \frac{2s}{(s^2 + 1)^2} = \frac{1}{s^2 + 1} + \frac{2s}{(s^2 + 1)^2}$$ Show more…

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Which of the following is equal to $$ \mathcal{L}^{-1} \left\{ \frac{s^2 + 2s + 1}{(s^2 + 1)^2} \right\} $$ if s > 0 ? (a) (1+t) sin t (b) t+tsinh t (c) t-tcos t (d) (1-t) sint (e) t-t/2 cosht