00:01
Hello student, here the question is given and the question is about the dna sequence.
00:04
So here this dna sequence is given and this dna sequence is from 5 prime to 3 prime and this is the tgc and then gcc, agc and then gag.
00:19
So this is the dna sequence is given and we have to answer the question regarding this sequence.
00:25
So the first question is regarding this complementary dna.
00:30
So we know the complementary dna is the one which is going to running from 3 prime to 5 prime direction and this a is always bind with the t and c is always bind with the g or the vice versa.
00:44
So here the t is the given so if we write the complementary sequences so the t is going to bind with the a and g is going to bind with the c.
00:52
Similarly this is going to be g and the cgg then t and this is going to be cgct and this is the c.
01:03
So this is the complementary sequences and this is the first question and the second question is regarding we have to tell the number of hydrogen bond.
01:12
So if we are calculating about these hydrogen bonds so we know in case of a and t there are two hydrogen bond in this two hydrogen bond present while in case of c and g there are three hydrogen bond.
01:28
So by calculating the number of adenine this at and the gc we can get this number of hydrogen bond.
01:37
So here the a and t is combination is only three and the rest one is going to be g and c.
01:44
So here two into this number of at at bonds and plus this three into number of gc bond.
01:58
So simply two into three and this is one going to be three into nine because the nine one is the total is 12 base pair.
02:06
So simply six plus 27 and it is going to be here we can get the number of total hydrogen bond...