00:01
We have the expression for chemmoe is equal to x alpha by 2 into sigma by root.
00:09
Now we then evaluate each of the sentences.
00:12
So for the first sentence, the evaluation is that when meo decreases, when temoe decreases, correspondingly n would have to be, 10 would have to be increased actually.
00:32
This is the correct thing that has to be happened.
00:36
So from the first statement given, the first statement given is not right or we can say that it is false.
00:48
The first statement given is false.
00:50
Now the second statement, it is said that when sigma decrease, correspondingly what happens to it.
00:58
That is what we have to evaluate.
01:01
As sigma decreases from the expression of mou, we can say that correspondingly meo will decrease.
01:13
Because it is in the numerator as the numerator decreases, the whole amount will be decreased.
01:19
Mouc decreases means that because from rearranging the expression of moe, you will have nd will see like this...