Which standard form of the equation of the hyperbola has vertices at (12, 0) and (–12, 0), and asymptotes
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Step 1
The vertices are given at (12, 0) and (–12, 0). The center of the hyperbola is the midpoint of the vertices. Center = \(\left(\frac{12 + (-12)}{2}, \frac{0 + 0}{2}\right) = (0, 0)\). Show more…
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