Write the vector expression for vecva and use this to find a...

Name: write the vector expression for vecva and use this to find a value for omegaab and so find the velocity vecva b 0 tab h a slider a is free to move horizontally o is a fixed point angle sh 20682
Uploaded: 2020-08-31T02:50:11-08:00
Duration: 7 min 3 s
Channel: Sheh Lit Chang
Description: write the vector expression for vecva and use this to find a value for omegaab and so find the velocity vecva b 0 tab h a slider a is free to move horizontally o is a fixed point angle sh 20682

Write the vector expression for ( vec{V}_{A} ) and use this to find a value for ( omega_{(A)/(B)} ) and so, find the velocity ( vec{V}_{A} ). B 0 TA/B h A Slider A is free to move horizontally O is a fixed point Angle shown is ( heta = 30^circ ) The fixed vertical distance h = 10 cm r_{L} = 50 cm r_{A/B} = 80 cm. The crank OB is rotating at 300 rpm Write the vector expression for ( vec{V} ) and use this to find a value for ( omega_{A/B} ) and so, find the velocity ( vec{V}_{A} )

Transcript

00:01 Ab, then is rotating at an angular velocity of 60 radiance per second.

00:07 We need to determine the velocity of slider c at the instance when theta is 60 degrees and 5 goes to 45 degrees.

00:15 And then after that, we need to sketch the position of bar bc when theta goes to 30 degrees, 60 degrees, and 90 degrees to show the general plane motion.

00:25 Okay, so yeah, given that omega ab is 60k regents per second and then we can first we need to find the velocity of point b.

00:40 Okay, this is just omega ab cross the position vector from a to b.

00:47 Okay, and then this is 60k cross 0 .3 minus sign 60 degrees i plus cosine 60 degrees j.

00:59 So we are using this coordinate system.

01:05 Usually this is a coordinate system you'll be using unless otherwise data.

01:10 So yeah, so data is 60 degrees.

01:14 So the icomponents minus sine 60 and the y component is cosine 60 degrees.

01:21 Okay.

01:22 And then if you simplify, this is what you get, 9 minus i minus root 3.

01:30 J meters per second okay so what happens is that this is square three over two and then this is half okay so okay then k cross i gives uh k cross i gives j and then we go minus i so minus j and k cross j is minus i so this is what we get okay then the next thing is we use the relative velocity equation.

02:08 So vc equals to vb plus omega bc cross the position vector of c relative to b.

02:20 So then from this situation, you can tell that vc is going to be pointing downward...

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