Yolanda pushes a box along a smooth horizontal surface with...

Name: yolanda pushes a box along a smooth horizontal surface with a force of 100 pounds at angle of 30o above the horizontal xavier pushes the same box from the opposite side with a force of 150 p 71773
Uploaded: 2020-04-29T16:27:04-08:00
Duration: 6 min 23 s
Channel: Charles Carter
Description: yolanda pushes a box along a smooth horizontal surface with a force of 100 pounds at angle of 30o above the horizontal xavier pushes the same box from the opposite side with a force of 150 p 71773

Yolanda pushes a box along a smooth, horizontal surface with a force of 100 pounds at angle of 30o above the horizontal. Xavier pushes the same box from the opposite side with a force of 150 pounds at angle of 25o above the horizontal. To solve the net force on the box, Adam subtracts the two forces as well as the angles. He comes up with 50 pounds at an angle of 5 o . Comment on Adam’s technique. Be clear in your explanation and do not solve the problem.

Transcript

00:01 Okay, so this problem is fairly lengthy, but it's not too bad.

00:04 So part a says to find the x and y components of f1.

00:09 Well, it says the force f1 is 20 pounds, 25 degrees above the horizontal.

00:16 So i guess we can call it f1 instead of you.

00:21 So our vector f1 will just equal our magnitude of the force, so 20 times cosine of the angle with the horizontal.

00:37 And then 20 times sign of the angle of the horizontal.

00:45 Okay, so the angle of the horizontal was 25 degrees.

00:50 So we just plug this into our calculator.

01:01 So our force from left to right is 18 .13.

01:11 And our force pulling upward is going to be 8 .45.

01:19 Those of these are in pounds.

01:25 Okay.

01:25 And then part b once the x and y components of force two so force two is going to be a counter to the motion of the block so it's only going to be going in the leftward direction so there's f1 there's f2 so it will not be pointing up or down so it's only going to be pointing to the left.

01:49 So let's do negative and it was five pounds and zero going up and down.

02:01 Okay, so part two c says use the answers to express the vector sum f1 plus f2 in terms of the components.

02:10 So all we have to do is add f1 and f2, so we're subtracting 5 from 18 .13.

02:16 And so f1 plus f2, a resulting force is going to be equal to 13 .13 and the original y value of just 8 .45...

Question

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