A water tank has the shape of an inverted circular cone with base radius 3 m and height 6 m. If water is pumped into the tank at a rate of 4 m^3/min, find the rate at which the water level is rising when the water is 2 m deep. V = 1/3?r^2h
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The volume of a cone is given by the formula V = (1/3)πr^2h, where r is the base radius and h is the height. Show more…
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A water tank has the shape of an inverted circular cone with a base radius of 2 meters and a height of 4 meters. If water is being pumped into the tank at a rate of 1 m^3/minute, find the rate at which the water level is rising when the water is 2 meters deep. (Exact answer)
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A container in the form of a right circular cone (vertex down) has radius $4 \mathrm{~m}$ and height $16 \mathrm{~m}$. See the figure. If water is poured into the container at the constant rate of $16 \mathrm{~m}^{3} / \mathrm{min}$, how fast is the water level rising when the water is $8 \mathrm{~m}$ deep? (Hint: The volume $V$ of a cone of radius $r$ and height $h$ is $\left.V=\frac{1}{3} \pi r^{2} h .\right)$
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