00:02
In this question we have been given a table of with values of x and y, we need to develop a finite difference.
00:25
Finite difference method using central divided difference approximation to solve this question as we know that double integration of wire divide by 7 .5.
01:31
So approximating d2 by dt square, we can write using central divided differencing equation d2 by dt square equal to y i plus 1 minus 2 .yi plus yi minus 1 divide by h square.
02:07
We can rewrite this equation.
02:11
Y i plus 1 minus 2 y i plus y i minus 1 .5 i minus 1 divide y h square equal to minus 0 .00 divide by 7 .5.
02:33
So substitute the value of h equal to 250 in this equation.
02:42
So we get yi plus 1 minus 2 .yi plus yi minus 1 minus 1.
03:00
Minus 0 .001 divided by 7 .5.
03:16
When we solve this equation, we get yi plus 1 minus 2 .yi plus y i minus 1 equal to minus 0 .8333 3 .3.
03:40
Suppose this is the equation number 1.
03:44
So for i equal to 1, we get y2 minus 2 y1 plus y0 equal to minus 0 .833.
04:09
So we know the value of y0, that is 10.
04:15
3 3 3 so when we solve this equation we can get y2 minus y2 equal to 2 y1 minus 10 point 8 3 3 3 this is the equation number 2 then for i equal to 2 we get y 3 3 3 minus 2y2 plus y1 equal to minus 0 .8333 so we can get the value y3 minus y3 minus 2 multiply put the value of y2 from equation number 2 to 2 y1 minus 10 .8 333 plus y1 equal to minus 0 .8333.
05:42
When we solve this equation we get y3 equal to 3y1 minus 22 .4999.
06:04
So this is the equation number 3.
06:10
Similarly, we can get for i equal to 3, we can solve y4.
06:16
So for y4 we get y4 equal to 4 y1 minus 34.
06:28
9 .9 .9 .8.
06:31
So this is the equation number 4...